-4(2x+3)=6(x+2)+11

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Solution for -4(2x+3)=6(x+2)+11 equation: 



-4(2x+3)=6(x+2)+11

We move all terms to the left:

-4(2x+3)-(6(x+2)+11)=0

We multiply parentheses

-8x-(6(x+2)+11)-12=0



We calculate terms in parentheses: -(6(x+2)+11), so:

6(x+2)+11

We multiply parentheses

6x+12+11

We add all the numbers together, and all the variables

6x+23

Back to the equation:

-(6x+23)



We get rid of parentheses

-8x-6x-23-12=0

We add all the numbers together, and all the variables

-14x-35=0

We move all terms containing x to the left, all other terms to the right

-14x=35

x=35/-14

x=-2+1/2

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