-4(2x+5)5x-1=-48

Solution for -4(2x+5)5x-1=-48 equation:

-4(2x+5)5x-1=-48

We move all terms to the left:

-4(2x+5)5x-1-(-48)=0

We add all the numbers together, and all the variables

-4(2x+5)5x+47=0

We multiply parentheses

-40x^2-100x+47=0

a = -40; b = -100; c = +47;
Δ = b2-4ac
Δ = -1002-4·(-40)·47
Δ = 17520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17520}=\sqrt{16*1095}=\sqrt{16}*\sqrt{1095}=4\sqrt{1095}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-4\sqrt{1095}}{2*-40}=\frac{100-4\sqrt{1095}}{-80}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+4\sqrt{1095}}{2*-40}=\frac{100+4\sqrt{1095}}{-80}
$