-4(2x-3)+5x=7(x+1)

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Solution for -4(2x-3)+5x=7(x+1) equation: 



-4(2x-3)+5x=7(x+1)

We move all terms to the left:

-4(2x-3)+5x-(7(x+1))=0

We add all the numbers together, and all the variables

5x-4(2x-3)-(7(x+1))=0

We multiply parentheses

5x-8x-(7(x+1))+12=0



We calculate terms in parentheses: -(7(x+1)), so:

7(x+1)

We multiply parentheses

7x+7

Back to the equation:

-(7x+7)



We add all the numbers together, and all the variables

-3x-(7x+7)+12=0

We get rid of parentheses

-3x-7x-7+12=0

We add all the numbers together, and all the variables

-10x+5=0

We move all terms containing x to the left, all other terms to the right

-10x=-5

x=-5/-10

x=1/2

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