-4(2x-3)-6x-2=3(-x+3)

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Solution for -4(2x-3)-6x-2=3(-x+3) equation: 



-4(2x-3)-6x-2=3(-x+3)

We move all terms to the left:

-4(2x-3)-6x-2-(3(-x+3))=0

We add all the numbers together, and all the variables

-4(2x-3)-6x-(3(-1x+3))-2=0

We add all the numbers together, and all the variables

-6x-4(2x-3)-(3(-1x+3))-2=0

We multiply parentheses

-6x-8x-(3(-1x+3))+12-2=0



We calculate terms in parentheses: -(3(-1x+3)), so:

3(-1x+3)

We multiply parentheses

-3x+9

Back to the equation:

-(-3x+9)



We add all the numbers together, and all the variables

-14x-(-3x+9)+10=0

We get rid of parentheses

-14x+3x-9+10=0

We add all the numbers together, and all the variables

-11x+1=0

We move all terms containing x to the left, all other terms to the right

-11x=-1

x=-1/-11

x=1/11

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