-4(2x-3)=2x+6-(8x-2)

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Solution for -4(2x-3)=2x+6-(8x-2) equation: 



-4(2x-3)=2x+6-(8x-2)

We move all terms to the left:

-4(2x-3)-(2x+6-(8x-2))=0

We multiply parentheses

-8x-(2x+6-(8x-2))+12=0



We calculate terms in parentheses: -(2x+6-(8x-2)), so:

2x+6-(8x-2)

determiningTheFunctionDomain
2x-(8x-2)+6

We get rid of parentheses

2x-8x+2+6

We add all the numbers together, and all the variables

-6x+8

Back to the equation:

-(-6x+8)



We get rid of parentheses

-8x+6x-8+12=0

We add all the numbers together, and all the variables

-2x+4=0

We move all terms containing x to the left, all other terms to the right

-2x=-4

x=-4/-2

x=+2

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