-4(2x-3)=8x-20

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Solution for -4(2x-3)=8x-20 equation: 



-4(2x-3)=8x-20

We move all terms to the left:

-4(2x-3)-(8x-20)=0

We multiply parentheses

-8x-(8x-20)+12=0

We get rid of parentheses

-8x-8x+20+12=0

We add all the numbers together, and all the variables

-16x+32=0

We move all terms containing x to the left, all other terms to the right

-16x=-32

x=-32/-16

x=+2

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