-4(2x-5)+12=3(3x+10)+13

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Solution for -4(2x-5)+12=3(3x+10)+13 equation: 



-4(2x-5)+12=3(3x+10)+13

We move all terms to the left:

-4(2x-5)+12-(3(3x+10)+13)=0

We multiply parentheses

-8x-(3(3x+10)+13)+20+12=0



We calculate terms in parentheses: -(3(3x+10)+13), so:

3(3x+10)+13

We multiply parentheses

9x+30+13

We add all the numbers together, and all the variables

9x+43

Back to the equation:

-(9x+43)



We add all the numbers together, and all the variables

-8x-(9x+43)+32=0

We get rid of parentheses

-8x-9x-43+32=0

We add all the numbers together, and all the variables

-17x-11=0

We move all terms containing x to the left, all other terms to the right

-17x=11

x=11/-17

x=-11/17

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