-4(2x-7)+4-3x=2(-2x-4)+6x+1

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Solution for -4(2x-7)+4-3x=2(-2x-4)+6x+1 equation: 



-4(2x-7)+4-3x=2(-2x-4)+6x+1

We move all terms to the left:

-4(2x-7)+4-3x-(2(-2x-4)+6x+1)=0

We add all the numbers together, and all the variables

-3x-4(2x-7)-(2(-2x-4)+6x+1)+4=0

We multiply parentheses

-3x-8x-(2(-2x-4)+6x+1)+28+4=0



We calculate terms in parentheses: -(2(-2x-4)+6x+1), so:

2(-2x-4)+6x+1

We add all the numbers together, and all the variables

6x+2(-2x-4)+1

We multiply parentheses

6x-4x-8+1

We add all the numbers together, and all the variables

2x-7

Back to the equation:

-(2x-7)



We add all the numbers together, and all the variables

-11x-(2x-7)+32=0

We get rid of parentheses

-11x-2x+7+32=0

We add all the numbers together, and all the variables

-13x+39=0

We move all terms containing x to the left, all other terms to the right

-13x=-39

x=-39/-13

x=+3

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