-4(2y-1)+5y=3(y+4)

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Solution for -4(2y-1)+5y=3(y+4) equation:



-4(2y-1)+5y=3(y+4)
We move all terms to the left:
-4(2y-1)+5y-(3(y+4))=0
We add all the numbers together, and all the variables
5y-4(2y-1)-(3(y+4))=0
We multiply parentheses
5y-8y-(3(y+4))+4=0
We calculate terms in parentheses: -(3(y+4)), so:
3(y+4)
We multiply parentheses
3y+12
Back to the equation:
-(3y+12)
We add all the numbers together, and all the variables
-3y-(3y+12)+4=0
We get rid of parentheses
-3y-3y-12+4=0
We add all the numbers together, and all the variables
-6y-8=0
We move all terms containing y to the left, all other terms to the right
-6y=8
y=8/-6
y=-1+1/3

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