-4(2y-10)-y=-3(y-4)

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Solution for -4(2y-10)-y=-3(y-4) equation: 



-4(2y-10)-y=-3(y-4)

We move all terms to the left:

-4(2y-10)-y-(-3(y-4))=0

We add all the numbers together, and all the variables

-1y-4(2y-10)-(-3(y-4))=0

We multiply parentheses

-1y-8y-(-3(y-4))+40=0



We calculate terms in parentheses: -(-3(y-4)), so:

-3(y-4)

We multiply parentheses

-3y+12

Back to the equation:

-(-3y+12)



We add all the numbers together, and all the variables

-9y-(-3y+12)+40=0

We get rid of parentheses

-9y+3y-12+40=0

We add all the numbers together, and all the variables

-6y+28=0

We move all terms containing y to the left, all other terms to the right

-6y=-28

y=-28/-6

y=4+2/3

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