-4(2y-4)+y=6+2(4y-1)

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Solution for -4(2y-4)+y=6+2(4y-1) equation: 



-4(2y-4)+y=6+2(4y-1)

We move all terms to the left:

-4(2y-4)+y-(6+2(4y-1))=0

We add all the numbers together, and all the variables

y-4(2y-4)-(6+2(4y-1))=0

We multiply parentheses

y-8y-(6+2(4y-1))+16=0



We calculate terms in parentheses: -(6+2(4y-1)), so:

6+2(4y-1)

determiningTheFunctionDomain
2(4y-1)+6

We multiply parentheses

8y-2+6

We add all the numbers together, and all the variables

8y+4

Back to the equation:

-(8y+4)



We add all the numbers together, and all the variables

-7y-(8y+4)+16=0

We get rid of parentheses

-7y-8y-4+16=0

We add all the numbers together, and all the variables

-15y+12=0

We move all terms containing y to the left, all other terms to the right

-15y=-12

y=-12/-15

y=4/5

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