-4(2y-5)-y=-2(y-3)

Solution for -4(2y-5)-y=-2(y-3) equation:

-4(2y-5)-y=-2(y-3)

We move all terms to the left:

-4(2y-5)-y-(-2(y-3))=0

We add all the numbers together, and all the variables

-1y-4(2y-5)-(-2(y-3))=0

We multiply parentheses

-1y-8y-(-2(y-3))+20=0


We calculate terms in parentheses: -(-2(y-3)), so:

-2(y-3)

We multiply parentheses

-2y+6

Back to the equation:

-(-2y+6)


We add all the numbers together, and all the variables

-9y-(-2y+6)+20=0

We get rid of parentheses

-9y+2y-6+20=0

We add all the numbers together, and all the variables

-7y+14=0

We move all terms containing y to the left, all other terms to the right

-7y=-14

y=-14/-7

y=+2