-4(2y-8)+4y=6(y+6)

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Solution for -4(2y-8)+4y=6(y+6) equation: 



-4(2y-8)+4y=6(y+6)

We move all terms to the left:

-4(2y-8)+4y-(6(y+6))=0

We add all the numbers together, and all the variables

4y-4(2y-8)-(6(y+6))=0

We multiply parentheses

4y-8y-(6(y+6))+32=0



We calculate terms in parentheses: -(6(y+6)), so:

6(y+6)

We multiply parentheses

6y+36

Back to the equation:

-(6y+36)



We add all the numbers together, and all the variables

-4y-(6y+36)+32=0

We get rid of parentheses

-4y-6y-36+32=0

We add all the numbers together, and all the variables

-10y-4=0

We move all terms containing y to the left, all other terms to the right

-10y=4

y=4/-10

y=-2/5

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