-4(2y-9)+2y=4(y+5)

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Solution for -4(2y-9)+2y=4(y+5) equation:



-4(2y-9)+2y=4(y+5)
We move all terms to the left:
-4(2y-9)+2y-(4(y+5))=0
We add all the numbers together, and all the variables
2y-4(2y-9)-(4(y+5))=0
We multiply parentheses
2y-8y-(4(y+5))+36=0
We calculate terms in parentheses: -(4(y+5)), so:
4(y+5)
We multiply parentheses
4y+20
Back to the equation:
-(4y+20)
We add all the numbers together, and all the variables
-6y-(4y+20)+36=0
We get rid of parentheses
-6y-4y-20+36=0
We add all the numbers together, and all the variables
-10y+16=0
We move all terms containing y to the left, all other terms to the right
-10y=-16
y=-16/-10
y=1+3/5

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