-4(2z-6)=-3(z+1)+z

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Solution for -4(2z-6)=-3(z+1)+z equation: 



-4(2z-6)=-3(z+1)+z

We move all terms to the left:

-4(2z-6)-(-3(z+1)+z)=0

We multiply parentheses

-8z-(-3(z+1)+z)+24=0



We calculate terms in parentheses: -(-3(z+1)+z), so:

-3(z+1)+z

We add all the numbers together, and all the variables

z-3(z+1)

We multiply parentheses

z-3z-3

We add all the numbers together, and all the variables

-2z-3

Back to the equation:

-(-2z-3)



We get rid of parentheses

-8z+2z+3+24=0

We add all the numbers together, and all the variables

-6z+27=0

We move all terms containing z to the left, all other terms to the right

-6z=-27

z=-27/-6

z=4+1/2

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