-4(3+3r)=8r-40

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Solution for -4(3+3r)=8r-40 equation: 



-4(3+3r)=8r-40

We move all terms to the left:

-4(3+3r)-(8r-40)=0

We add all the numbers together, and all the variables

-4(3r+3)-(8r-40)=0

We multiply parentheses

-12r-(8r-40)-12=0

We get rid of parentheses

-12r-8r+40-12=0

We add all the numbers together, and all the variables

-20r+28=0

We move all terms containing r to the left, all other terms to the right

-20r=-28

r=-28/-20

r=1+2/5

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