-4(3+y)+6y-12=-36

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Solution for -4(3+y)+6y-12=-36 equation: 



-4(3+y)+6y-12=-36

We move all terms to the left:

-4(3+y)+6y-12-(-36)=0

We add all the numbers together, and all the variables

-4(y+3)+6y-12-(-36)=0

We add all the numbers together, and all the variables

6y-4(y+3)+24=0

We multiply parentheses

6y-4y-12+24=0

We add all the numbers together, and all the variables

2y+12=0

We move all terms containing y to the left, all other terms to the right

2y=-12

y=-12/2

y=-6

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