-4(3-4b)-2b=-4b+-4(b+3)

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Solution for -4(3-4b)-2b=-4b+-4(b+3) equation: 



-4(3-4b)-2b=-4b+-4(b+3)

We move all terms to the left:

-4(3-4b)-2b-(-4b+-4(b+3))=0

We add all the numbers together, and all the variables

-4(-4b+3)-2b-(-4b+-4(b+3))=0

We add all the numbers together, and all the variables

-2b-4(-4b+3)-(-4b+-4(b+3))=0

We use the square of the difference formula

-2b-4(-4b+3)-(-4b-4(b+3))=0

We multiply parentheses

-2b+16b-(-4b-4(b+3))-12=0



We calculate terms in parentheses: -(-4b-4(b+3)), so:

-4b-4(b+3)

We multiply parentheses

-4b-4b-12

We add all the numbers together, and all the variables

-8b-12

Back to the equation:

-(-8b-12)



We add all the numbers together, and all the variables

14b-(-8b-12)-12=0

We get rid of parentheses

14b+8b+12-12=0

We add all the numbers together, and all the variables

22b=0

b=0/22

b=0

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