-4(3-k)/3=2(k+6)/5

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Solution for -4(3-k)/3=2(k+6)/5 equation:



-4(3-k)/3=2(k+6)/5
We move all terms to the left:
-4(3-k)/3-(2(k+6)/5)=0
We add all the numbers together, and all the variables
-4(-1k+3)/3-(2(k+6)/5)=0
We calculate fractions
4k/()+(-(2(k+6)*3)/()=0
We calculate terms in parentheses: +(-(2(k+6)*3)/(), so:
-(2(k+6)*3)/(
We multiply all the terms by the denominator
-(2(k+6)*3)
We calculate terms in parentheses: -(2(k+6)*3), so:
2(k+6)*3
We multiply parentheses
6k+36
Back to the equation:
-(6k+36)
We get rid of parentheses
-6k-36
Back to the equation:
+(-6k-36)
We get rid of parentheses
4k/()-6k-36=0
We multiply all the terms by the denominator
4k-6k*()-36*()=0
We add all the numbers together, and all the variables
4k-6k*()=0

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