-4(3a+2)-12=16

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Solution for -4(3a+2)-12=16 equation: 



-4(3a+2)-12=16

We move all terms to the left:

-4(3a+2)-12-(16)=0

We add all the numbers together, and all the variables

-4(3a+2)-28=0

We multiply parentheses

-12a-8-28=0

We add all the numbers together, and all the variables

-12a-36=0

We move all terms containing a to the left, all other terms to the right

-12a=36

a=36/-12

a=-3

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