-4(3a+2)=40+4a

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Solution for -4(3a+2)=40+4a equation: 



-4(3a+2)=40+4a

We move all terms to the left:

-4(3a+2)-(40+4a)=0

We add all the numbers together, and all the variables

-4(3a+2)-(4a+40)=0

We multiply parentheses

-12a-(4a+40)-8=0

We get rid of parentheses

-12a-4a-40-8=0

We add all the numbers together, and all the variables

-16a-48=0

We move all terms containing a to the left, all other terms to the right

-16a=48

a=48/-16

a=-3

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