-4(3a+5)=3(4-4a)-32

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Solution for -4(3a+5)=3(4-4a)-32 equation: 


Simplifying
-4(3a + 5) = 3(4 + -4a) + -32

Reorder the terms:
-4(5 + 3a) = 3(4 + -4a) + -32
(5 * -4 + 3a * -4) = 3(4 + -4a) + -32
(-20 + -12a) = 3(4 + -4a) + -32
-20 + -12a = (4 * 3 + -4a * 3) + -32
-20 + -12a = (12 + -12a) + -32

Reorder the terms:
-20 + -12a = 12 + -32 + -12a

Combine like terms: 12 + -32 = -20
-20 + -12a = -20 + -12a

Add '20' to each side of the equation.
-20 + 20 + -12a = -20 + 20 + -12a

Combine like terms: -20 + 20 = 0
0 + -12a = -20 + 20 + -12a
-12a = -20 + 20 + -12a

Combine like terms: -20 + 20 = 0
-12a = 0 + -12a
-12a = -12a

Add '12a' to each side of the equation.
-12a + 12a = -12a + 12a

Combine like terms: -12a + 12a = 0
0 = -12a + 12a

Combine like terms: -12a + 12a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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