-4(3b+1)+(13b-2)=0

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Solution for -4(3b+1)+(13b-2)=0 equation:


Simplifying
-4(3b + 1) + (13b + -2) = 0

Reorder the terms:
-4(1 + 3b) + (13b + -2) = 0
(1 * -4 + 3b * -4) + (13b + -2) = 0
(-4 + -12b) + (13b + -2) = 0

Reorder the terms:
-4 + -12b + (-2 + 13b) = 0

Remove parenthesis around (-2 + 13b)
-4 + -12b + -2 + 13b = 0

Reorder the terms:
-4 + -2 + -12b + 13b = 0

Combine like terms: -4 + -2 = -6
-6 + -12b + 13b = 0

Combine like terms: -12b + 13b = 1b
-6 + 1b = 0

Solving
-6 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 1b = 0 + 6

Combine like terms: -6 + 6 = 0
0 + 1b = 0 + 6
1b = 0 + 6

Combine like terms: 0 + 6 = 6
1b = 6

Divide each side by '1'.
b = 6

Simplifying
b = 6

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