-4(3b+1)+(13b-6)=0

Solution for -4(3b+1)+(13b-6)=0 equation:

Simplifying
-4(3b + 1) + (13b + -6) = 0

Reorder the terms:
-4(1 + 3b) + (13b + -6) = 0
(1 * -4 + 3b * -4) + (13b + -6) = 0
(-4 + -12b) + (13b + -6) = 0

Reorder the terms:
-4 + -12b + (-6 + 13b) = 0

Remove parenthesis around (-6 + 13b)
-4 + -12b + -6 + 13b = 0

Reorder the terms:
-4 + -6 + -12b + 13b = 0

Combine like terms: -4 + -6 = -10
-10 + -12b + 13b = 0

Combine like terms: -12b + 13b = 1b
-10 + 1b = 0

Solving
-10 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 1b = 0 + 10

Combine like terms: -10 + 10 = 0
0 + 1b = 0 + 10
1b = 0 + 10

Combine like terms: 0 + 10 = 10
1b = 10

Divide each side by '1'.
b = 10

Simplifying
b = 10