-4(3b+1)+(13b-8)=0

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Solution for -4(3b+1)+(13b-8)=0 equation:


Simplifying
-4(3b + 1) + (13b + -8) = 0

Reorder the terms:
-4(1 + 3b) + (13b + -8) = 0
(1 * -4 + 3b * -4) + (13b + -8) = 0
(-4 + -12b) + (13b + -8) = 0

Reorder the terms:
-4 + -12b + (-8 + 13b) = 0

Remove parenthesis around (-8 + 13b)
-4 + -12b + -8 + 13b = 0

Reorder the terms:
-4 + -8 + -12b + 13b = 0

Combine like terms: -4 + -8 = -12
-12 + -12b + 13b = 0

Combine like terms: -12b + 13b = 1b
-12 + 1b = 0

Solving
-12 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 1b = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 1b = 0 + 12
1b = 0 + 12

Combine like terms: 0 + 12 = 12
1b = 12

Divide each side by '1'.
b = 12

Simplifying
b = 12

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