-4(3b-3)-7(b+4)=79

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Solution for -4(3b-3)-7(b+4)=79 equation: 



-4(3b-3)-7(b+4)=79

We move all terms to the left:

-4(3b-3)-7(b+4)-(79)=0

We multiply parentheses

-12b-7b+12-28-79=0

We add all the numbers together, and all the variables

-19b-95=0

We move all terms containing b to the left, all other terms to the right

-19b=95

b=95/-19

b=-5

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