-4(3c-1)+3c=-3(2c+6)+5

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Solution for -4(3c-1)+3c=-3(2c+6)+5 equation: 



-4(3c-1)+3c=-3(2c+6)+5

We move all terms to the left:

-4(3c-1)+3c-(-3(2c+6)+5)=0

We add all the numbers together, and all the variables

3c-4(3c-1)-(-3(2c+6)+5)=0

We multiply parentheses

3c-12c-(-3(2c+6)+5)+4=0



We calculate terms in parentheses: -(-3(2c+6)+5), so:

-3(2c+6)+5

We multiply parentheses

-6c-18+5

We add all the numbers together, and all the variables

-6c-13

Back to the equation:

-(-6c-13)



We add all the numbers together, and all the variables

-9c-(-6c-13)+4=0

We get rid of parentheses

-9c+6c+13+4=0

We add all the numbers together, and all the variables

-3c+17=0

We move all terms containing c to the left, all other terms to the right

-3c=-17

c=-17/-3

c=5+2/3

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