-4(3k-2)+3=24+k

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Solution for -4(3k-2)+3=24+k equation: 



-4(3k-2)+3=24+k

We move all terms to the left:

-4(3k-2)+3-(24+k)=0

We add all the numbers together, and all the variables

-4(3k-2)-(k+24)+3=0

We multiply parentheses

-12k-(k+24)+8+3=0

We get rid of parentheses

-12k-k-24+8+3=0

We add all the numbers together, and all the variables

-13k-13=0

We move all terms containing k to the left, all other terms to the right

-13k=13

k=13/-13

k=-1

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