-4(3m+5)=-2(1m-2)

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Solution for -4(3m+5)=-2(1m-2) equation: 



-4(3m+5)=-2(1m-2)

We move all terms to the left:

-4(3m+5)-(-2(1m-2))=0

We add all the numbers together, and all the variables

-4(3m+5)-(-2(m-2))=0

We multiply parentheses

-12m-(-2(m-2))-20=0



We calculate terms in parentheses: -(-2(m-2)), so:

-2(m-2)

We multiply parentheses

-2m+4

Back to the equation:

-(-2m+4)



We get rid of parentheses

-12m+2m-4-20=0

We add all the numbers together, and all the variables

-10m-24=0

We move all terms containing m to the left, all other terms to the right

-10m=24

m=24/-10

m=-2+2/5

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