-4(3n-2)-n=-11(n-15)

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Solution for -4(3n-2)-n=-11(n-15) equation: 



-4(3n-2)-n=-11(n-15)

We move all terms to the left:

-4(3n-2)-n-(-11(n-15))=0

We add all the numbers together, and all the variables

-1n-4(3n-2)-(-11(n-15))=0

We multiply parentheses

-1n-12n-(-11(n-15))+8=0



We calculate terms in parentheses: -(-11(n-15)), so:

-11(n-15)

We multiply parentheses

-11n+165

Back to the equation:

-(-11n+165)



We add all the numbers together, and all the variables

-13n-(-11n+165)+8=0

We get rid of parentheses

-13n+11n-165+8=0

We add all the numbers together, and all the variables

-2n-157=0

We move all terms containing n to the left, all other terms to the right

-2n=157

n=157/-2

n=-78+1/2

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