-4(3n-2)n=-11(n-1)

Solution for -4(3n-2)n=-11(n-1) equation:

-4(3n-2)n=-11(n-1)

We move all terms to the left:

-4(3n-2)n-(-11(n-1))=0

We multiply parentheses

-12n^2+8n-(-11(n-1))=0


We calculate terms in parentheses: -(-11(n-1)), so:

-11(n-1)

We multiply parentheses

-11n+11

Back to the equation:

-(-11n+11)


We get rid of parentheses

-12n^2+8n+11n-11=0

We add all the numbers together, and all the variables

-12n^2+19n-11=0

a = -12; b = 19; c = -11;
Δ = b2-4ac
Δ = 192-4·(-12)·(-11)
Δ = -167
Delta is less than zero, so there is no solution for the equation