-4(3n-2n)-n=-11(n-1)

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Solution for -4(3n-2n)-n=-11(n-1) equation: 



-4(3n-2n)-n=-11(n-1)

We move all terms to the left:

-4(3n-2n)-n-(-11(n-1))=0

We add all the numbers together, and all the variables

-4(+n)-n-(-11(n-1))=0

We add all the numbers together, and all the variables

-1n-4(+n)-(-11(n-1))=0

We multiply parentheses

-1n-4n-(-11(n-1))=0



We calculate terms in parentheses: -(-11(n-1)), so:

-11(n-1)

We multiply parentheses

-11n+11

Back to the equation:

-(-11n+11)



We add all the numbers together, and all the variables

-5n-(-11n+11)=0

We get rid of parentheses

-5n+11n-11=0

We add all the numbers together, and all the variables

6n-11=0

We move all terms containing n to the left, all other terms to the right

6n=11

n=11/6

n=1+5/6

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