-4(3r-5)=39+7r

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Solution for -4(3r-5)=39+7r equation: 



-4(3r-5)=39+7r

We move all terms to the left:

-4(3r-5)-(39+7r)=0

We add all the numbers together, and all the variables

-4(3r-5)-(7r+39)=0

We multiply parentheses

-12r-(7r+39)+20=0

We get rid of parentheses

-12r-7r-39+20=0

We add all the numbers together, and all the variables

-19r-19=0

We move all terms containing r to the left, all other terms to the right

-19r=19

r=19/-19

r=-1

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