-4(3u-3)+8u=6(u+3)

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Solution for -4(3u-3)+8u=6(u+3) equation: 



-4(3u-3)+8u=6(u+3)

We move all terms to the left:

-4(3u-3)+8u-(6(u+3))=0

We add all the numbers together, and all the variables

8u-4(3u-3)-(6(u+3))=0

We multiply parentheses

8u-12u-(6(u+3))+12=0



We calculate terms in parentheses: -(6(u+3)), so:

6(u+3)

We multiply parentheses

6u+18

Back to the equation:

-(6u+18)



We add all the numbers together, and all the variables

-4u-(6u+18)+12=0

We get rid of parentheses

-4u-6u-18+12=0

We add all the numbers together, and all the variables

-10u-6=0

We move all terms containing u to the left, all other terms to the right

-10u=6

u=6/-10

u=-3/5

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