-4(3v-3)+8v=4+2(2v-1)

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Solution for -4(3v-3)+8v=4+2(2v-1) equation: 



-4(3v-3)+8v=4+2(2v-1)

We move all terms to the left:

-4(3v-3)+8v-(4+2(2v-1))=0

We add all the numbers together, and all the variables

8v-4(3v-3)-(4+2(2v-1))=0

We multiply parentheses

8v-12v-(4+2(2v-1))+12=0



We calculate terms in parentheses: -(4+2(2v-1)), so:

4+2(2v-1)

determiningTheFunctionDomain
2(2v-1)+4

We multiply parentheses

4v-2+4

We add all the numbers together, and all the variables

4v+2

Back to the equation:

-(4v+2)



We add all the numbers together, and all the variables

-4v-(4v+2)+12=0

We get rid of parentheses

-4v-4v-2+12=0

We add all the numbers together, and all the variables

-8v+10=0

We move all terms containing v to the left, all other terms to the right

-8v=-10

v=-10/-8

v=1+1/4

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