-4(3v-5)+8v=6(v+3)

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Solution for -4(3v-5)+8v=6(v+3) equation: 



-4(3v-5)+8v=6(v+3)

We move all terms to the left:

-4(3v-5)+8v-(6(v+3))=0

We add all the numbers together, and all the variables

8v-4(3v-5)-(6(v+3))=0

We multiply parentheses

8v-12v-(6(v+3))+20=0



We calculate terms in parentheses: -(6(v+3)), so:

6(v+3)

We multiply parentheses

6v+18

Back to the equation:

-(6v+18)



We add all the numbers together, and all the variables

-4v-(6v+18)+20=0

We get rid of parentheses

-4v-6v-18+20=0

We add all the numbers together, and all the variables

-10v+2=0

We move all terms containing v to the left, all other terms to the right

-10v=-2

v=-2/-10

v=1/5

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