-4(3x+1)x-3=15

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Solution for -4(3x+1)x-3=15 equation: 



-4(3x+1)x-3=15

We move all terms to the left:

-4(3x+1)x-3-(15)=0

We add all the numbers together, and all the variables

-4(3x+1)x-18=0

We multiply parentheses

-12x^2-4x-18=0

a = -12; b = -4; c = -18;
Δ = b2-4ac
Δ = -42-4·(-12)·(-18)
Δ = -848
Delta is less than zero, so there is no solution for the equation

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