-4(3x+2)=2x+6-(8x-2)

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Solution for -4(3x+2)=2x+6-(8x-2) equation: 



-4(3x+2)=2x+6-(8x-2)

We move all terms to the left:

-4(3x+2)-(2x+6-(8x-2))=0

We multiply parentheses

-12x-(2x+6-(8x-2))-8=0



We calculate terms in parentheses: -(2x+6-(8x-2)), so:

2x+6-(8x-2)

determiningTheFunctionDomain
2x-(8x-2)+6

We get rid of parentheses

2x-8x+2+6

We add all the numbers together, and all the variables

-6x+8

Back to the equation:

-(-6x+8)



We get rid of parentheses

-12x+6x-8-8=0

We add all the numbers together, and all the variables

-6x-16=0

We move all terms containing x to the left, all other terms to the right

-6x=16

x=16/-6

x=-2+2/3

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