-4(3x-2)+12=-20

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Solution for -4(3x-2)+12=-20 equation: 



-4(3x-2)+12=-20

We move all terms to the left:

-4(3x-2)+12-(-20)=0

We add all the numbers together, and all the variables

-4(3x-2)+32=0

We multiply parentheses

-12x+8+32=0

We add all the numbers together, and all the variables

-12x+40=0

We move all terms containing x to the left, all other terms to the right

-12x=-40

x=-40/-12

x=3+1/3

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