-4(3x-2)+x=15x-3(2x+5)

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Solution for -4(3x-2)+x=15x-3(2x+5) equation: 



-4(3x-2)+x=15x-3(2x+5)

We move all terms to the left:

-4(3x-2)+x-(15x-3(2x+5))=0

We add all the numbers together, and all the variables

x-4(3x-2)-(15x-3(2x+5))=0

We multiply parentheses

x-12x-(15x-3(2x+5))+8=0



We calculate terms in parentheses: -(15x-3(2x+5)), so:

15x-3(2x+5)

We multiply parentheses

15x-6x-15

We add all the numbers together, and all the variables

9x-15

Back to the equation:

-(9x-15)



We add all the numbers together, and all the variables

-11x-(9x-15)+8=0

We get rid of parentheses

-11x-9x+15+8=0

We add all the numbers together, and all the variables

-20x+23=0

We move all terms containing x to the left, all other terms to the right

-20x=-23

x=-23/-20

x=1+3/20

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