-4(3x-8)+8=-12x+40

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Solution for -4(3x-8)+8=-12x+40 equation:


Simplifying
-4(3x + -8) + 8 = -12x + 40

Reorder the terms:
-4(-8 + 3x) + 8 = -12x + 40
(-8 * -4 + 3x * -4) + 8 = -12x + 40
(32 + -12x) + 8 = -12x + 40

Reorder the terms:
32 + 8 + -12x = -12x + 40

Combine like terms: 32 + 8 = 40
40 + -12x = -12x + 40

Reorder the terms:
40 + -12x = 40 + -12x

Add '-40' to each side of the equation.
40 + -40 + -12x = 40 + -40 + -12x

Combine like terms: 40 + -40 = 0
0 + -12x = 40 + -40 + -12x
-12x = 40 + -40 + -12x

Combine like terms: 40 + -40 = 0
-12x = 0 + -12x
-12x = -12x

Add '12x' to each side of the equation.
-12x + 12x = -12x + 12x

Combine like terms: -12x + 12x = 0
0 = -12x + 12x

Combine like terms: -12x + 12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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