-4(3x-8)=-6x+20

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Solution for -4(3x-8)=-6x+20 equation: 



-4(3x-8)=-6x+20

We move all terms to the left:

-4(3x-8)-(-6x+20)=0

We multiply parentheses

-12x-(-6x+20)+32=0

We get rid of parentheses

-12x+6x-20+32=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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