-4(3y+-7)=40

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Solution for -4(3y+-7)=40 equation: 



-4(3y+-7)=40

We move all terms to the left:

-4(3y+-7)-(40)=0

We add all the numbers together, and all the variables

-4(3y-7)-40=0

We multiply parentheses

-12y+28-40=0

We add all the numbers together, and all the variables

-12y-12=0

We move all terms containing y to the left, all other terms to the right

-12y=12

y=12/-12

y=-1

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