-4(3y+2)-13=-6(y+7)+3y

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Solution for -4(3y+2)-13=-6(y+7)+3y equation: 



-4(3y+2)-13=-6(y+7)+3y

We move all terms to the left:

-4(3y+2)-13-(-6(y+7)+3y)=0

We multiply parentheses

-12y-(-6(y+7)+3y)-8-13=0



We calculate terms in parentheses: -(-6(y+7)+3y), so:

-6(y+7)+3y

We add all the numbers together, and all the variables

3y-6(y+7)

We multiply parentheses

3y-6y-42

We add all the numbers together, and all the variables

-3y-42

Back to the equation:

-(-3y-42)



We add all the numbers together, and all the variables

-12y-(-3y-42)-21=0

We get rid of parentheses

-12y+3y+42-21=0

We add all the numbers together, and all the variables

-9y+21=0

We move all terms containing y to the left, all other terms to the right

-9y=-21

y=-21/-9

y=2+1/3

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