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-4(3y+4)=2(5-6y)-29
We move all terms to the left:
-4(3y+4)-(2(5-6y)-29)=0
We add all the numbers together, and all the variables
-4(3y+4)-(2(-6y+5)-29)=0
We multiply parentheses
-12y-(2(-6y+5)-29)-16=0
We calculate terms in parentheses: -(2(-6y+5)-29), so:We get rid of parentheses
2(-6y+5)-29
We multiply parentheses
-12y+10-29
We add all the numbers together, and all the variables
-12y-19
Back to the equation:
-(-12y-19)
-12y+12y+19-16=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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