-4(3y+5)=3(3-4y)-29

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Solution for -4(3y+5)=3(3-4y)-29 equation:


Simplifying
-4(3y + 5) = 3(3 + -4y) + -29

Reorder the terms:
-4(5 + 3y) = 3(3 + -4y) + -29
(5 * -4 + 3y * -4) = 3(3 + -4y) + -29
(-20 + -12y) = 3(3 + -4y) + -29
-20 + -12y = (3 * 3 + -4y * 3) + -29
-20 + -12y = (9 + -12y) + -29

Reorder the terms:
-20 + -12y = 9 + -29 + -12y

Combine like terms: 9 + -29 = -20
-20 + -12y = -20 + -12y

Add '20' to each side of the equation.
-20 + 20 + -12y = -20 + 20 + -12y

Combine like terms: -20 + 20 = 0
0 + -12y = -20 + 20 + -12y
-12y = -20 + 20 + -12y

Combine like terms: -20 + 20 = 0
-12y = 0 + -12y
-12y = -12y

Add '12y' to each side of the equation.
-12y + 12y = -12y + 12y

Combine like terms: -12y + 12y = 0
0 = -12y + 12y

Combine like terms: -12y + 12y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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