-4(3y-2)+8y=2(y+3)

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Solution for -4(3y-2)+8y=2(y+3) equation: 



-4(3y-2)+8y=2(y+3)

We move all terms to the left:

-4(3y-2)+8y-(2(y+3))=0

We add all the numbers together, and all the variables

8y-4(3y-2)-(2(y+3))=0

We multiply parentheses

8y-12y-(2(y+3))+8=0



We calculate terms in parentheses: -(2(y+3)), so:

2(y+3)

We multiply parentheses

2y+6

Back to the equation:

-(2y+6)



We add all the numbers together, and all the variables

-4y-(2y+6)+8=0

We get rid of parentheses

-4y-2y-6+8=0

We add all the numbers together, and all the variables

-6y+2=0

We move all terms containing y to the left, all other terms to the right

-6y=-2

y=-2/-6

y=1/3

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