-4(3y-2)=2(-6y+4)

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Solution for -4(3y-2)=2(-6y+4) equation: 



-4(3y-2)=2(-6y+4)

We move all terms to the left:

-4(3y-2)-(2(-6y+4))=0

We multiply parentheses

-12y-(2(-6y+4))+8=0



We calculate terms in parentheses: -(2(-6y+4)), so:

2(-6y+4)

We multiply parentheses

-12y+8

Back to the equation:

-(-12y+8)



We get rid of parentheses

-12y+12y-8+8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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