-4(3y-3)+2y=8+2(2y-7)

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Solution for -4(3y-3)+2y=8+2(2y-7) equation: 



-4(3y-3)+2y=8+2(2y-7)

We move all terms to the left:

-4(3y-3)+2y-(8+2(2y-7))=0

We add all the numbers together, and all the variables

2y-4(3y-3)-(8+2(2y-7))=0

We multiply parentheses

2y-12y-(8+2(2y-7))+12=0



We calculate terms in parentheses: -(8+2(2y-7)), so:

8+2(2y-7)

determiningTheFunctionDomain
2(2y-7)+8

We multiply parentheses

4y-14+8

We add all the numbers together, and all the variables

4y-6

Back to the equation:

-(4y-6)



We add all the numbers together, and all the variables

-10y-(4y-6)+12=0

We get rid of parentheses

-10y-4y+6+12=0

We add all the numbers together, and all the variables

-14y+18=0

We move all terms containing y to the left, all other terms to the right

-14y=-18

y=-18/-14

y=1+2/7

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