-4(3y-3)+7y=5(y+2)

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Solution for -4(3y-3)+7y=5(y+2) equation: 



-4(3y-3)+7y=5(y+2)

We move all terms to the left:

-4(3y-3)+7y-(5(y+2))=0

We add all the numbers together, and all the variables

7y-4(3y-3)-(5(y+2))=0

We multiply parentheses

7y-12y-(5(y+2))+12=0



We calculate terms in parentheses: -(5(y+2)), so:

5(y+2)

We multiply parentheses

5y+10

Back to the equation:

-(5y+10)



We add all the numbers together, and all the variables

-5y-(5y+10)+12=0

We get rid of parentheses

-5y-5y-10+12=0

We add all the numbers together, and all the variables

-10y+2=0

We move all terms containing y to the left, all other terms to the right

-10y=-2

y=-2/-10

y=1/5

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